ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:57Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
68K
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
λ = h/p