ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:59Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 2 ; 3 6 | = 24
302K
∑_{k=1}^{n} k = n(n+1)/2
312K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 8 4 ; 6 9 | = 48
264K
10β² + 6β + 6 = 0
det| 11 5 ; 0 12 | = 132
39K