ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:38Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 4 6 ; 0 5 | = 20
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∫₀^∞ e^(-r²) dr = √π / 2
det| 11 5 ; 0 12 | = 132
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12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
\frac{4}{6} \sum_{i=1}^{n} i^{2}
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O