ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:03Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-ω²) dω = √π / 2
302K
4β² + 5β + 0 = 0
det| 7 7 ; 4 8 | = 28
125K
d/dφ [φ^6] = 6φ^5
∑_{k=1}^{n} k = n(n+1)/2
17K
det| 9 4 ; 1 10 | = 86
310K
det| 11 9 ; 5 12 | = 87
311K
det| 9 2 ; 3 10 | = 84
264K