ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 10 4 ; 1 11 | = 106
312K
12φ² + 6φ + 4 = 0
det| 7 4 ; 4 8 | = 40
125K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
91K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-ω²) dω = √π / 2
17K
5φ² + 5φ + 0 = 0