ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 02:04Z
4α² + 9α + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
∫₀^∞ e^(-y²) dy = √π / 2
det| 1 9 ; 6 2 | = -52
∑_{k=1}^{n} k = n(n+1)/2
17K
det| 9 4 ; 1 10 | = 86
310K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-ω²) dω = √π / 2
311K
∑_{k=1}^{n} k = n(n+1)/2
264K
det| 11 9 ; 0 12 | = 132
39K