ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:44Z
10n² + 5n + 0 = 0
E = mc²
det| 11 5 ; 0 12 | = 132
91K
det| 8 7 ; 7 9 | = 23
det| 7 4 ; 4 8 | = 40
310K
d/dt [t^11] = 11t^10
∫₀^∞ e^(-y²) dy = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
68K
∫₀^∞ e^(-θ²) dθ = √π / 2
39K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
6K