ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 16:56Z
∇²β = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
257K
11y² + 3y + 2 = 0
∇ × E = −∂B/∂t
\lim_{x\to 0} \frac{\sin x}{x} = 1
det| 1 7 ; 5 2 | = -33
∑_{k=1}^{n} k = n(n+1)/2
22K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
479K