ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:06Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
302K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 2 7 ; 7 3 | = -43
311K
∫₀^∞ e^(-θ²) dθ = √π / 2
264K
det| 9 1 ; 7 10 | = 83
68K