ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:03Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K