ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:28Z
N₂ + 3H₂ ⇌ 2NH₃
12φ² + 6φ + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
91K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
5φ² + 5φ + 0 = 0
det| 9 1 ; 7 10 | = 83
311K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 7 7 ; 5 8 | = 21