ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:02Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
4β² + 5β + 0 = 0
det| 4 6 ; 0 5 | = 20
91K
d/dφ [φ^6] = 6φ^5
det| 7 4 ; 4 8 | = 40
17K
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
6n² + 3n + 0 = 0
det| 2 7 ; 7 3 | = -43
311K
10β² + 6β + 6 = 0
det| 1 8 ; 4 2 | = -30
68K
F = ma
d/dα [α^1] = 1α^0