ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 19:02Z
d/dr [r^5] = 5r^4
∫₀^∞ e^(-ω²) dω = √π / 2
312K
2x² + 4x + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
17K
\lim_{α\to 0} \frac{\sin α}{α} = 1
310K
det| 11 7 ; 6 12 | = 90
∫₀^∞ e^(-x²) dx = √π / 2
311K
7ω² + 6ω + 0 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
68K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 2 ; 4 10 | = 82
\oint_C \vec{F}\cdot d\vec{r} = 0