ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:31Z
iħ ∂ψ/∂t = Ĥψ
det| 11 9 ; 0 12 | = 132
259K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
231K
5ω² + 9ω + 6 = 0
det| 9 5 ; 6 10 | = 60
22K
∫₀^∞ e^(-α²) dα = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃