ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
d/dz [z^11] = 11z^10
302K
12φ² + 6φ + 4 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
125K
2H₂ + O₂ → 2H₂O
\frac{4}{6} \sum_{i=1}^{n} i^{2}
17K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
5φ² + 5φ + 0 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
det| 7 4 ; 4 8 | = 40
68K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
39K