ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:25Z
∫₀^∞ e^(-φ²) dφ = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
257K
det| 10 2 ; 5 11 | = 100
det| 12 1 ; 5 13 | = 151
270K
PV = nRT
det| 7 4 ; 4 8 | = 40
437K
∫₀^∞ e^(-θ²) dθ = √π / 2
442K
7y² + 8y + 2 = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
231K
9n² + 7n + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{1}{5} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0