ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:39Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-r²) dr = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
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det| 9 4 ; 1 10 | = 86
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12γ² + 2γ + 2 = 0
E = mc²
det| 3 7 ; 2 4 | = -2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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λ = h/p
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t