ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:36Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
AgNO₃ + NaCl → AgCl↓ + NaNO₃
312K
∫₀^∞ e^(-r²) dr = √π / 2
det| 7 1 ; 7 8 | = 49
125K
12γ² + 2γ + 2 = 0
E = mc²
det| 5 3 ; 2 6 | = 24
311K
det| 5 9 ; 7 6 | = -33
264K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O