ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:32Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∑_{k=1}^{n} k = n(n+1)/2
93K
\frac{11}{6} \sum_{i=1}^{n} i^{2}
211K
∫₀^∞ e^(-α²) dα = √π / 2
det| 7 4 ; 4 8 | = 40
453K
7y² + 6y + 1 = 0
det| 4 8 ; 0 5 | = 20
133K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
177K
E = mc²
det| 9 5 ; 1 10 | = 85
45K
∫₀^∞ e^(-β²) dβ = √π / 2
207K
∇²y = 0
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1