ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:37Z
7φ² + 7φ + 6 = 0
det| 3 7 ; 2 4 | = -2
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
9n² + 8n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
ΔS ≥ 0
∫₀^∞ e^(-n²) dn = √π / 2
264K
E = mc²
det| 7 4 ; 4 8 | = 40
68K
det| 9 1 ; 7 10 | = 83
39K
det| 9 5 ; 6 10 | = 60
6K