ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:26Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
312K
∫₀^∞ e^(-r²) dr = √π / 2
\frac{6}{7} \sum_{i=1}^{n} i^{2}
91K
12γ² + 2γ + 2 = 0
det| 7 4 ; 4 8 | = 40
17K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K
∑_{k=1}^{n} k = n(n+1)/2
364K