ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:55Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
312K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
∑_{k=1}^{n} k = n(n+1)/2
17K
6n² + 3n + 0 = 0
det| 9 4 ; 1 10 | = 86
264K
10β² + 6β + 6 = 0
det| 7 8 ; 4 8 | = 24
68K
F = ma
Fe₂O₃ + 3CO → 2Fe + 3CO₂
364K
∫₀^∞ e^(-β²) dβ = √π / 2
6K
det| 10 8 ; 4 11 | = 78