ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:27Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{α\to 0} \frac{\sin α}{α} = 1
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∫₀^∞ e^(-r²) dr = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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12γ² + 2γ + 2 = 0
det| 3 7 ; 2 4 | = -2
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E = mc²
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
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λ = h/p
det| 9 5 ; 6 10 | = 60
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O