ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:24Z
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 7 4 ; 4 8 | = 40
259K
det| 1 4 ; 3 2 | = -10
257K
det| 10 2 ; 5 11 | = 100
∑_{k=1}^{n} k = n(n+1)/2
159K
PV = nRT
d/dz [z^11] = 11z^10
437K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
442K
7y² + 8y + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
231K
9n² + 7n + 4 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
202K
\frac{6}{6} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O