ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:23Z
10n² + 5n + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
302K
∫₀^∞ e^(-z²) dz = √π / 2
312K
E = mc²
det| 8 7 ; 7 9 | = 23
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
17K
d/dt [t^11] = 11t^10
det| 11 5 ; 0 12 | = 132
311K
det| 9 2 ; 3 10 | = 84
6K