ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:32Z
iħ ∂ψ/∂t = Ĥψ
det| 1 4 ; 2 2 | = -6
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
∑_{k=1}^{n} k = n(n+1)/2
270K
∇²t = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
202K
∑_{k=1}^{n} k = n(n+1)/2
22K
det| 2 3 ; 5 3 | = -9
479K
det| 7 4 ; 4 8 | = 40
205K