ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:12Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
302K
∇²ω = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
AgNO₃ + NaCl → AgCl↓ + NaNO₃
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
311K
CH₄ + 2O₂ → CO₂ + 2H₂O
264K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0