ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:04Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
302K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
312K
4β² + 5β + 0 = 0
det| 11 9 ; 5 12 | = 87
125K
det| 5 6 ; 1 6 | = 24
91K
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
311K
det| 11 9 ; 0 12 | = 132
264K
∑_{k=1}^{n} k = n(n+1)/2
68K
det| 9 4 ; 1 10 | = 86
364K