ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-ω²) dω = √π / 2
302K
12φ² + 6φ + 4 = 0
2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
310K
5φ² + 5φ + 0 = 0
det| 5 3 ; 2 6 | = 24
311K
∑_{k=1}^{n} k = n(n+1)/2
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
68K
ΔS ≥ 0
∫₀^∞ e^(-β²) dβ = √π / 2