ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:48Z
iħ ∂ψ/∂t = Ĥψ
det| 9 4 ; 1 10 | = 86
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
270K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
AgNO₃ + NaCl → AgCl↓ + NaNO₃
193K
5ω² + 9ω + 6 = 0
det| 1 8 ; 4 2 | = -30
202K
∫₀^∞ e^(-α²) dα = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃