ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:08Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 9 ; 0 12 | = 132
312K
∇²ω = 0
\frac{6}{3} \sum_{i=1}^{n} i^{2}
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
2H₂ + O₂ → 2H₂O
iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0