ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
312K
12φ² + 6φ + 4 = 0
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
det| 9 2 ; 3 10 | = 84
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
68K
∫₀^∞ e^(-x²) dx = √π / 2
39K
ΔS ≥ 0
e^{i\pi} + 1 = 0