ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:28Z
N₂ + 3H₂ ⇌ 2NH₃
12φ² + 6φ + 4 = 0
det| 7 8 ; 4 8 | = 24
125K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
310K
5φ² + 5φ + 0 = 0
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 4 6 | = 6
364K