ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:54Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
12γ² + 2γ + 2 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
311K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}