ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
E = mc²
det| 11 9 ; 5 12 | = 87
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\oint_C \vec{F}\cdot d\vec{r} = 0
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λ = h/p
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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