ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:41Z
7φ² + 7φ + 6 = 0
det| 4 8 ; 0 5 | = 20
302K
∫₀^∞ e^(-β²) dβ = √π / 2
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
125K
9n² + 8n + 4 = 0
det| 7 4 ; 4 8 | = 40
17K
det| 1 2 ; 7 2 | = -12
310K
ΔS ≥ 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
264K
E = mc²
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30
det| 3 5 ; 7 4 | = -23
F = ma
∇²y = 0