ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:20Z
10n² + 5n + 0 = 0
E = mc²
det| 3 1 ; 7 4 | = 5
125K
det| 7 4 ; 4 8 | = 40
91K
det| 8 7 ; 7 9 | = 23
∫₀^∞ e^(-x²) dx = √π / 2
17K
d/dt [t^11] = 11t^10
∫₀^∞ e^(-y²) dy = √π / 2
det| 5 9 ; 7 6 | = -33
68K