ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:35Z
iħ ∂ψ/∂t = Ĥψ
AgNO₃ + NaCl → AgCl↓ + NaNO₃
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
159K
∇²t = 0
det| 3 1 ; 7 4 | = 5
442K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
5ω² + 9ω + 6 = 0
∫₀^∞ e^(-α²) dα = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃