ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:39Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 9 1 ; 7 10 | = 83
312K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
det| 9 4 ; 1 10 | = 86
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E = mc²
∫₀^∞ e^(-θ²) dθ = √π / 2
311K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}