ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:35Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 7 4 ; 4 8 | = 40
312K
CaCO₃ → CaO + CO₂
8t² + 2t + 1 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
17K
∑_{k=1}^{n} k = n(n+1)/2
310K