ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:56Z
7φ² + 7φ + 6 = 0
det| 7 7 ; 4 8 | = 28
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
9n² + 8n + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
310K
ΔS ≥ 0
det| 7 4 ; 4 8 | = 40
264K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃