ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:56Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
det| 7 4 ; 4 8 | = 40
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
2H₂ + O₂ → 2H₂O
iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0