ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:56Z
7φ² + 7φ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\frac{11}{6} \sum_{i=1}^{n} i^{2}
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
9n² + 8n + 4 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
ΔS ≥ 0
det| 9 1 ; 7 10 | = 83
311K
det| 7 4 ; 4 8 | = 40
264K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃