ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:47Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 9 4 ; 1 10 | = 86
311K
det| 5 3 ; 2 6 | = 24
264K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0