ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:23Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
312K
∫₀^∞ e^(-r²) dr = √π / 2
det| 3 1 ; 7 4 | = 5
125K
12γ² + 2γ + 2 = 0
det| 9 4 ; 1 10 | = 86
17K
E = mc²
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O