ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:18Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
302K
det| 9 1 ; 7 10 | = 83
312K
CaCO₃ → CaO + CO₂
8t² + 2t + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
∑_{k=1}^{n} k = n(n+1)/2
311K
∫₀^∞ e^(-β²) dβ = √π / 2
68K