ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:28Z
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 12 1 ; 5 13 | = 151
259K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
257K
det| 10 2 ; 5 11 | = 100
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
159K
PV = nRT
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
442K
7y² + 8y + 2 = 0
det| 9 4 ; 1 10 | = 86
231K
∑_{k=1}^{n} k = n(n+1)/2
193K
9n² + 7n + 4 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
202K
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O