ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:20Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-β²) dβ = √π / 2
312K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
det| 9 8 ; 3 10 | = 66
310K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}