ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:57Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
d/dφ [φ^6] = 6φ^5
det| 7 7 ; 4 8 | = 28
310K
6n² + 3n + 0 = 0
det| 9 4 ; 1 10 | = 86
311K
CH₄ + 2O₂ → CO₂ + 2H₂O
264K