ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:35Z
10n² + 5n + 0 = 0
det| 7 4 ; 4 8 | = 40
302K
E = mc²
det| 8 7 ; 7 9 | = 23
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
d/dt [t^11] = 11t^10
∑_{k=1}^{n} k = n(n+1)/2
311K
∫₀^∞ e^(-y²) dy = √π / 2
det| 3 7 ; 2 4 | = -2
68K
det| 4 8 ; 1 5 | = 12
∫₀^∞ e^(-n²) dn = √π / 2
364K
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃